Check whether a number is Armstrong Number or not using C++ programming

A number is Armstrong number only if the sum of cubes of every individual digits of that number is equal to the number itself. For example 153 is an Armstrong number as 1³ + 5³ + 3³ = 153. Some other Armstrong numbers are: 0, 1, 153, 370, 407. But 123 is not a Armstrong number as 1³ + 2³ + 3³ = 36.
Let’s write the program

#include<iostream>
using namespace std;
main()
{   int i=0,n,m,k;
    cout<<"Enter Your Number";
    cin>>n;
m=n;
while(n!=0)
    {   k=(n%10);
        i=i+k*k*k;
        n=n/10;
    }
    if(i==m)
    {   cout<<"This number is Armstrong";
    }
    else
    {   cout<<"This number is Not Armstrong";
    }
}

The output of above program is

Enter Your Number 153
This number is Armstrong

Enter Your Number 123
This number is Not Armstrong